Divisible by 3
Define a function named div_3 that returns True if its single integer parameter is divisible by 3 and False otherwise.
For example, div_3(6) is True because 6/3 does not leave any remainder. However div_3(5) is False because 5/3 leaves 2 as a remainder.
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==== SOLUTION ====
You can implement the `div_3` function in Python by checking if the given integer is divisible by 3 without leaving any remainder. Here’s how you can do it:
“`python
def div_3(n):
     return n % 3 == 0
# Test the function
print(div_3(6)) # Output: True
print(div_3(5)) # Output: False
“`
Explanation:
1. `def div_3(n):`: This line defines a function named `div_3` that takes a single integer parameter `n`.
2. `return n % 3 == 0`: This line returns `True` if `n` is divisible by 3 without leaving any remainder (i.e., the result of `n % 3` is 0), and `False` otherwise.
So, when you call `div_3(6)`, it returns `True` because 6 is divisible by 3 without leaving any remainder. Similarly, when you call `div_3(5)`, it returns `False` because 5 is not divisible by 3 without leaving a remainder.
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